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upward How about 3 units to the right Will the w value go off the scale Let s plug in v = 3 and see what we get: w = 7 3 10 = 21 10 = 11 It s still in the field of view, so we can plot (3, 11) on the plane as a small open circle, and draw the line for the first equation through it and (0, 10) There s no doubt that we need to find a more distant point on the line for the second equation In SI form, that equation is w = ( 1/2)v 5 so the slope is 1/2 Knowing this and the w-intercept, we can get a good idea of the position and orientation of the line It passes through the point (0, 5), ramps gradually downward as

E w2 2w w + 2 w E w2 2 w (413)

we move to the right, and ramps gradually upward as we move to the left Let s plug in v = 12 and calculate: w = ( 1/2) ( 12) 5 =6 5 =1 This is in the field of view, so we can plot the point ( 12, 1) as a small open circle, and draw the line for the second equation through it and (0, 5)

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'-----------------------------------------------------------------------------------------------------------------------------' Name : Frog-testbas ' Compiler : PicBasic Pro MicroEngineering Labs ' Notes : Program to test the main controller ' : board by flashing LEDs, producing ' : sounds and slowly rotating the servos '-----------------------------------------------------------------------------------------------------------------------------' set porta to inputs trisa = %11111111 ' set portb pins 2 & 3 to inputs trisb = %00001100 '-----------------------------------------------------------------------------------------------------------------------------' initialize variables servo_pos_l VAR BYTE servo_pos_r VAR BYTE timer1 VAR BYTE timer2 VAR BYTE timer3 VAR BYTE temp1 VAR BYTE servo_r VAR PORTB5 servo_l VAR PORTB6

Example 43 Compute the mean, second moment, variance, and standard deviation of the random variable x with the exponential density px (X) = where > 0 The mean is x =

What happens when one of the lines in a graph has an undefined slope How can you solve and graph a linear system such as this, for example y = 2x 2 and x=3 You can t reduce the second equation to SI form Its graph is a vertical line passing through (3, 0) The first equation has a slope of 2 Because this sloping line extends forever both ways, upward and to the right as well as downward and to the left, it must cross the vertical line x = 3, which extends forever straight upward and straight downward, at some point This is a perfectly decent two-by-two linear system For extra credit, you can solve it and graph it

exp( X) 0

Here s a trick!

switch_r VAR PORTA4 switch_l VAR PORTA3 led_l VAR PORTB1 led_r VAR PORTB0 piezo VAR PORTB4 '-----------------------------------------------------------------------------------------------------------------------------low servo_l low servo_r start: for temp1 = 1 to 10 SOUND piezo, [80,4,100,2] low led_l low led_r pause 50 high led_l high led_r next temp1 SOUND piezo, [100,4,120,2,80,2,90,2] low led_l low led_r rotate: servo_pos_r = 170 gosub right_servo servo_pos_l = 130 gosub left_servo goto rotate '-----------------------------------------------------------------------------------------------------------------------------' subroutines to set servos both_servo: for timer1 = 1 to 15 pulsout servo_l,servo_pos_l pulsout servo_r,servo_pos_r pause 6 next timer1 return left_servo: for timer2 = 1 to 10

1

Look again at the system we graphed in Fig 17-5 The original two equations are: 7v + w + 10 = 0 and 4v + 8w = 40 Suppose we want to draw a graph of this system with w as the independent variable and v as the dependent variable Instead of deriving the SI versions all over again with the variables reversed, we can do a trick with the coordinate system and the lines drawn on it For a minute, imagine Fig 17-5 as an unbreakable unit with the axes, points, and lines all glued together The positive v axis goes toward the right and the positive w axis goes upward Now think: How can we morph this figure so the positive w axis goes toward the right and the positive v axis goes upward If we can do that, we ll end up with a graph of the two-by-two linear system with w as the independent variable and v as the dependent variable Actually, this process takes only three steps We rotate the drawing in Fig 17-5 by 90 (one-quarter of a turn) counterclockwise Then we mirror the drawing left-to-right Finally, we relabel the points by

Solution = ( 16/3,2/3)

0

( 10,0) ( 5,0) Each axis increment is 2 units (1, 12)

frog-testbas program listing (continued)

2 2

4v + 8w = 40 as a two-by-two linear system where the independent variable is w and the dependent variable is v This graph was obtained by rotating Fig 17-5 by 90 counterclockwise, mirroring it right-to-left, and relabeling the points

2 The variance is x = 0 (v x )2 exp( v)dv, but can also be easily calculate from the information above using the eqn (413) as

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