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---------------------------------------------------------------------- Function: fn_subordinates1, Descendants --- Input : @root INT: Manager id --- Output : @Subs Table: id and level of subordinates of -input manager (empid = @root) in all levels --- Process : * Insert into @Subs row of input manager -* In a loop, while previous insert loaded more than 0 rows -insert into @Subs next level of subordinates --------------------------------------------------------------------USE tempdb; GO IF OBJECT_ID('dbo.fn_subordinates1') IS NOT NULL DROP FUNCTION dbo.fn_subordinates1; GO CREATE FUNCTION dbo.fn_subordinates1(@root AS INT) RETURNS @Subs TABLE ( empid INT NOT NULL PRIMARY KEY NONCLUSTERED, lvl INT NOT NULL, UNIQUE CLUSTERED(lvl, empid) -- Index will be used to filter level ) AS BEGIN DECLARE @lvl AS INT; SET @lvl = 0; -- Initialize level counter with 0 -- Insert root node into @Subs INSERT INTO @Subs(empid, lvl) SELECT empid, @lvl FROM dbo.Employees WHERE empid = @root; WHILE @@rowcount > 0 BEGIN SET @lvl = @lvl + 1; -- while previous level had rows -- Increment level counter

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dr = cmd.ExecuteReader(CommandBehavior.CloseConnection) dr.Read will return true if data exists. ValidateUser = dr.Read() Catch e As Exception ValidateUser = False End Try End Function End Class

-- Insert next level of subordinates to @Subs INSERT INTO @Subs(empid, lvl) SELECT C.empid, @lvl FROM @Subs AS P -- P = Parent JOIN dbo.Employees AS C -- C = Child ON P.lvl = @lvl - 1 -- Filter parents from previous level AND C.mgrid = P.empid;

using System.Web.Mvc; using System.Web.Routing; public static class AppRoutes { public static void RegisterRoutes(RouteCollection routes) { routes.MapRoute( "Home",

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The function accepts the @root input parameter, which is the ID of the requested subtree's root employee. The function returns the @Subs table variable, with all subordinates of employee with ID = @root in all levels. Besides containing the employee attributes, @Subs also has a column called lvl that keeps track of the level in the subtree (0 for the subtree's root, and increasing from there by 1 in each iteration). The function's code keeps track of the current level being handled in the @lvl local variable, which is initialized with zero. The function's code first inserts into @Subs the row from Employees where empid = @root. Then in a loop, while the last insert affects more than zero rows, the code increments the @lvl variable's value by one and loads to @Subs the next level of employeesin other words, direct subordinates of the managers loaded in the previous level. To load the next level of employees to @Subs, the query in the loop joins @Subs (representing managers) with Employees (representing subordinates). The lvl column is important because it allows you to isolate the managers that were inserted into @Subs in the last iteration. To return only subordinates of the previously inserted managers, the join condition filters from @Subs only rows where the lvl column is equal to the previous level (@lvl 1). To test the function, run the following code, which returns the subordinates of employee 3, as shown in Table 9-6: SELECT empid, lvl FROM dbo.fn_subordinates1(3) AS S;

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The single exposed method of the GetGolfArticle XML Web service is GetArticle. This method accepts four parameters, ArticleDate, Author, UserName, and Password. The first, ArticleDate, is declared as a String rather than a Date. Declaring the date as a String allows the service to accept invalid dates as input and behave in some reasonable way. The ArticleDate parameter is a ByRef parameter because I might want to modify the date. The stored procedure called to actually retrieve the article from the database can accept either a valid date or a null; the default value is null. When the date passed to the stored procedure is null, the stored procedure gets the most recent article by the specified author. The stored procedure, spSelectArticle, is shown in Listing 10-8. Listing 10-8 Stored procedure to select article by date or the most recent article

You can verify that the output is correct by examining Figure 9-2 and following the subtree of the root employee (ID = 3). To get other attributes of the employees besides just the employee ID, you can either rewrite the function and add those attributes to the @Subs table, or simply join the function with the Employees table like so: SELECT E.empid, E.empname, S.lvl FROM dbo.fn_subordinates1(3) AS S JOIN dbo.Employees AS E ON E.empid = S.empid;

You will get the output shown in Table 9-7.

CREATE PROCEDURE spSelectArticle @Author nvarchar(50), @ArticleDate datetime = null AS SET NOCOUNT ON

To limit the result set to leaf employees under the given root, simply add a filter with a NOT EXISTS predicate to select only employees that are not managers of other employees: SELECT empid FROM dbo.fn_subordinates1(3) AS P WHERE NOT EXISTS (SELECT * FROM dbo.Employees AS C WHERE c.mgrid = P.empid);

This query returns employee IDs 11, 12, 13, and 14. So far, you've seen the UDF implementation of a subtree under a given root. Listing 9-5 has the CTE solution (SQL Server 2005 only).

string.Empty, new { controller = "Surveys", action = "Index" }); routes.MapRoute( "ViewSurvey", "survey/{tenant}/{surveySlug}", new { controller = "Surveys", action = "Display" }); routes.MapRoute( "ThankYouForFillingTheSurvey", "survey/{tenant}/{surveySlug}/thankyou", new { controller = "Surveys", action = "ThankYou" }); } }

If NULL passed in, then IF IsNull(@ArticleDate, 19000101 )= 19000101 BEGIN SET @ArticleDate=GetDate() END

DECLARE @root AS INT; SET @root = 3; WITH SubsCTE AS ( -- Anchor member returns root node SELECT empid, empname, 0 AS lvl FROM dbo.Employees WHERE empid = @root UNION ALL -- Recursive member returns next level of children SELECT C.empid, C.empname, P.lvl + 1 FROM SubsCTE AS P JOIN dbo.Employees AS C ON C.mgrid = P.empid ) SELECT * FROM SubsCTE;

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